Question

Two years ago, a man's age was three times the square of his son's age . In three years time, his age will be four times his son's age.Find their present ages.

Answer 1

LET AT PRESENT, FATHER'S AGE=M AND SON'S AGE=S

I.E. M-2=3$(S-2{)}^2$

I.E. M=3S^2-12S+14........................1

ALSO M+3=4(S+3)=4S+12

I.E. M=4S+9..........................2

FROM 1 & 2, 3S^2-12S+14=4S+9

I.E. 3S^2-16S+5=0

I.E. EITHER S=5 OR $S=1/3$

BECAUSE S CAN'T BE 1/3, THEREFORE S=5,

BY PUTTING IN 2, WE GET,

M=4S+9=29,

I.E. AT PRESENT, MAN'S AGE=29 AND SON'S AGE=5