Question

Two years ago, Dilip was three times as old as his son and two years hence, twice his age will be equal to five times that of his son. Then the present age of Dilip is what?

Answer 1

.Let Dilip's sons present age be x and his sons present age be y
2yrs ago
3(y-2)=x-2
3y-6=x-2
3y-x=4.
that is 2x-6y=-8. eq1
2yrs after
2(x+2)=5(y+2)
2x+4=5y+10
2x-5y=6. eq2
subtracting eq1 by eq2
2x-6y-2x+5y=-8-6
-y=-14
y=14
substituting y in eq2
2x-5(14)=6
2x=6+70
x=76/2
x=38
Hence Dilip's present age is 38 yrs