Let salim and his daughter’s age be x and y yr respectively
Now, by first condition
Two years ago, salim was thrice as old as his daughter
i.e., x−2=3(y−2)⇒x−2=3y−6⇒ x−3y=−4
and by second condition, six years later. Salim will be four years older than twice her age.
x + 6 = 2 (y + 6 ) + 4
⇒ x + 6 = 2y + 12 + 4
⇒ x – 2y = 16 – 6
⇒ x – 2y = 10
On subtracting Eq. (i) from Eq. (ii), we get
x−2y=10x−3y=−4 –––––––––––– y=14
put the value of in Eq. (ii) we get
x – 2y × 14 = 10
x = 10 + 28 ⇒ x = 38
hence, salim and his daughter’s age are 38 yr and 14 yr respectively.