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Question

Two years ago, sumitra was five times as old as her daughter, and eight years hence , the mother will be thrice old as her daughter. Find thier present ages.

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Solution

Let the age of daughter 2 years ago = x yrsThen the age of Sumitra, 2 yrs ago = 5x yrsPresent age of daughter = x+2 yrsPresent age of Sumitra = 5x+2 yrsAfter 8 years :Daughter's age = x+10 yrsSumitra's age = 5x+10 yrsAccording to question,5x + 10 = 3x+105x + 10 = 3x + 305x - 3x = 30 - 102x = 20x = 10So, present age of daughter = x+2 = 10 + 2 = 12 yrspresent age of Sumitra = 5x + 2 = 5×10+2 = 50+2 = 52 yrs

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