Type of hybridization of central atom of gas (B) is:
A
sp
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B
sp2
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C
sp3
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D
No hybridization
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Solution
The correct option is Bsp2 2Pb(NO3)2(A)Δ−→2PbO+4NO2↑(B)+O2↑Pb(NO3)2(A)+H2S→PbS↓(F)PbS(F)+dil.HNO3→Pb(NO3)2+NO↑(H)+H2O(G)Pb(NO3)2(A)+K2CrO4→PbCrO4↓(I)+2KNO3NO2(B)+NO(H)very low temp.−−−−−−−−→N2O3(C)N2O3(C)+H2O→2HNO2(D)2HNO2(D)+2FeSO4+H2SO4→Fe2(SO4)3+2NO+2H2OFeSO4+NO→[Fe(H2O)5NO]SO4(E)
Gas (B) i.e. NO2 is an odd electron species. Due to the higher electronegativity of O, this odd electron on N takes part in hybridization. Thus, the hydridization of N in NO2 is sp2.