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Question

Type of terms and corresponding number is written in Column 2 and Column 3 respectively of the Binomial in Column 1.
Column I Column II Column 3(I)(516+719)1824(i)Total number of rational terms(P)4(II)(516+218)100(ii)Total number of irrational terms(Q)102(III)(314+413)99(iii)12[Total number of termsNumber of rational terms],(R)224 where [.]represents greatest integer function. (IV)(713+1119)2007(iv)Total number of terms(S)Is divisible by 13
Select the correct combination

A
(I) (iv) (R)
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B
(II) (i) (S)
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C
(I) (i) (Q)
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D
(III) (ii) (P)
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Solution

The correct option is C (I) (i) (Q)
(I) Tr+1=1824Cr(51/6)1824r(71/9)r
=1824Cr5304r67r9
r6 and r9 must be integers so r must be the LCM of 6 and 9 i.e. 18
r = 0, 18, 36, 1818
1818 = 0 + (λ - 1) 18
102 = Total rational terms
1825 - 102 = 1723 = total irrational terms
Total number of terms = 1825

(II)Tr+1=100Cr(51/6)100r2r8
100r6 and r8 must be integers for rational terms
r = 0, 8, 16, 24 88, 96
100 - r = 100, 92, 84 12, 4
r = 16, 40, 64, 88 for 100r6 and r8 to be integers
So, total rational terms = 4
total terms = 101
total irrational terms = 97

(III) (314+413)99=(314+223)99
Tr+1=99Cr(314)99r22r3
for rational terms
99r4 and 2r3 must be integers
r = 0, 3, 6 99
99 - r = 99, 96, 93 3, 0
99r4 and 2r3 must be integers for rational terms
Hence 99 - r = 0, 12, 24, 36, 48, 60, 72, 84, 96
Total rational terms = 9
Total terms = 100
Hence irrational terms = 91

(IV) Tr+1=2007Cr72007r311r9;for rational terms 2007r3, r9 must be integers
r = 0, 9, 18, 2007
So, total rational terms = 224
Total irrational terms = 2008 - 224 = 1784
Total terms = 2008

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