The correct option is C (I) (i) (Q)
(I) Tr+1=1824Cr(51/6)1824−r(71/9)r
=1824Cr5304−r67r9
r6 and r9 must be integers so r must be the LCM of 6 and 9 i.e. 18
r = 0, 18, 36, ⋯ 1818
1818 = 0 + (λ - 1) 18
102 = Total rational terms
1825 - 102 = 1723 = total irrational terms
Total number of terms = 1825
(II)Tr+1=100Cr(51/6)100−r2r8
100−r6 and r8 must be integers for rational terms
r = 0, 8, 16, 24 ⋯ 88, 96
100 - r = 100, 92, 84 ⋯ 12, 4
r = 16, 40, 64, 88 for 100−r6 and r8 to be integers
So, total rational terms = 4
total terms = 101
total irrational terms = 97
(III) (314+413)99=(314+223)99
Tr+1=99Cr(314)99−r22r3
for rational terms
99−r4 and 2r3 must be integers
r = 0, 3, 6 ⋯ 99
99 - r = 99, 96, 93 ⋯ 3, 0
99−r4 and 2r3 must be integers for rational terms
Hence 99 - r = 0, 12, 24, 36, 48, 60, 72, 84, 96
Total rational terms = 9
Total terms = 100
Hence irrational terms = 91
(IV) Tr+1=2007Cr72007−r311r9;for rational terms 2007−r3, r9 must be integers
r = 0, 9, 18, ⋯ 2007
So, total rational terms = 224
Total irrational terms = 2008 - 224 = 1784
Total terms = 2008