U-235 can decay by many ways, let us here consider only two ways, A and B. In decay of U-235 by means of A, the energy released per fission is 210MeV while in B it is 186MeV. Then, the uranium-235 sample is more likely to decay by
A
scheme A
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B
scheme B
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C
equally likely for both schemes
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D
it depends on half-life of schemes A and B
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Solution
The correct option is B scheme A Every atom has a tendency to reach the lowest energy state to be most stable. The more the energy released, the higher will be the binding energy/nucleon in the products and hence more stability. Hence A is more likely.