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Alpha Decay

U with atomic...

Question

U with atomic number 92 and mass number 238 is radioactive and it emits alpha and beta particles to form Pb with atomic number 82 and mass number 206. Calculate the number of alpha and beta particles emitted in this conversation.

An ore of U with atomic number 92 and mass number 238 is found to contain U and Pb in the weight ratio of 1:0.1. The half-life period of U is $4.5 \times 10^{9}$ years. Calculate the age of the ore.

$6.7 \times 10^{9}$

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$7.12 \times 10^{8}$

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$8.5 \times 10^{10}$

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$6.6 \times 10^{9}$

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Solution

The correct option is B
$7.12 \times 10^{8}$

Watch the video for the solution

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Similar questions

_{92}^{238} U

is radioactive and it emits

α

and

β

-particles to form

_{82}^{206} P b

. An ore of

_{92}^{238} U

is found to contain

_{92}^{238} U

and

_{82}^{206} P b

in the weight ratio of 1 : 0.1. The half-life period of

_{92}^{238} U

4.5 \times 10^{9}

years. Calculate the age of the ore?

Thorium with atomic number 92 and mass number 238 disintegrates to give Pb with atomic number 82 and mass number 206. How many alpha and beta particles are emitted during this process?

Q. In the nuclear reaction

_{92} U^{238} \to_{82} P b^{206}

the number of

α

and

β

-particles emitted is

Q. ( a ) Calculate number of

α

and

β -

particles emitted when

_{92} U^{238}

changes into radioactive

_{82} P b^{206} .

( b )

T h^{234}

disintegrates and emits

6 β -

and

7 α -

particles to form a stable element. Find the atomic number and
mass number of the stable product. Also identify the element:

Q. The number of alpha and

β

particles emitted when

_{92}^{238} U

is finally converted into

_{82}^{206} P b

is:

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The correct option is B 7.12×108 Watch the video for the solution

The correct option is B
$7.12 \times 10^{8}$

Watch the video for the solution