Equation is : 5p + 2 = 17
By hit and trial method, put p = 1
5(1) + 2 = 7≠17
Now put p = 2 we get
5(2) + 2 = 12 ≠17
Now put p = 3 we get
5(3)+2=17 = R.H.S
The value of p is 3.
Question 3(i) Solve the following equation by trial and error method: 5p+ 2 = 17
Solve the following equations by trial and error method:
(i) 5p + 2 = 17 (ii) 3m − 14 = 4
Solve the following equations by trial and error method:(i) 5p+2=17(ii) 3m−14=4
Solve the following equations by trial and errormethod:
(1)x−10=5
(2)a7+8=6
(3)x2+6=9
(4)19=x+13
(5)x4=9
(6)2x+4=3x−4