Under a constant Electric field of 5 N/C, a positive charge moves such that its Kinetic energy is increased by 10 J. Assuming no other force acting, the work done by the field is?

10 J

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-10 J

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0 J

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None of these

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Solution

The correct option is A
10 J

If the charge gains Kinetic energy, it's very evident that something must have done positive work on it.
As there is no other force acting on it, Electric field itself must have done +10J work.

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Under a constant Electric field of 5 N/C, a positive charge moves such that its Kinetic energy is increased by 10 J. Assuming no other force acting, the work done by the field is?

The correct option is A 10 J If the charge gains Kinetic energy, it's very evident that something must have done positive work on it. As there is no other force acting on it, Electric field itself must have done +10J work.

The correct option is A
10 J

If the charge gains Kinetic energy, it's very evident that something must have done positive work on it.
As there is no other force acting on it, Electric field itself must have done +10J work.