Question

Under ambient conditions, the total number of gases released as products in the final step of the reaction scheme shown below is:

• A. 1
• B. 2
• C. 3

Answer 1

The correct option is B 2

$Xe{F}_6+3H_{2}O\to Xe{O}_3+\underset{\left(P\right)}{6HF}$
$\underset{\left(P\right)}{Xe{O}_3}+O{H}^{-}/H_{2}O\to \underset{\left(Q\right)}{HXe{O}_4^{-}}$
$\underset{\left(Q\right)}{2HXe{O}_4^{-}}\to Xe\uparrow +Xe{O}_6^{4-}+O_2\uparrow +H_{2}O$
Hence, there are two gaseous products $Xe$ and $O_2$.