Under ambient conditions, the total number of gases released products in the final step of the reaction scheme shown below is

(IIT-JEE Advanced, 2014)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B 2
$X e F_{6} + 3 H_{2} O \to X e O_{3} + 6 H F$
(P)
$X e O_{3} + O H^{⊖} \to H X e O_{4}^{⊖}$
(P) (Q)
$2 H X e O_{4}^{⊖} + 2 O H^{⊖} \to X e O_{6}^{4 -} + X e_{(g)} + 2 H_{2} O + O_{2 (g)}$
(Q)
Gases are Xe and $O_{2} .$

Suggest Corrections

Similar questions

X e F_{6} C o m p l e t e H y d r o l y s i s - ------------ \to P + other product

↓ O H^{-} / H_{2} O

Q

↓ slow disproportionation in O H^{-} / H_{2} O

I^{⊖} + C l O_{3}^{⊖} + H_{2} S O_{4} \to C l^{⊖} + H S O_{4}^{-} + I_{2}

Join BYJU'S Learning Program