Question

Under constant pressure, the temperature of 3 mol of an ideal monoatomic gas is raised by 15 K. What is the change in average kinetic energy per atom?

• A. 0.00194 eV
• B. 1.021 eV
• C. 0.2171 eV
• D. 0.0352 eV

Answer 1

The correct option is A

0.00194 eV

Since,

$(K.E)=\frac{3}{2}{K}_{B}T,permolecule,$

Change in {K.E} for a change in tempreture will be -

$\Delta (K.E)=\frac{3}{2}{K}_B\Delta T$

$=(\frac{3}{2}\times 1.38\times {10}^{-23}\times 15)\times (6.242\times {10}^{18})eV$

$=1.94\times {10}^{-3}eV.$