Under identical experiment conditions of the following pairs of gases will be most easy to separate by using effusion process:

H_{2}

and

T_{2}

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S O_{2}

and

S O_{3}

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N H_{3}

and CH_4$

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U^{235} O_{2}

and

U^{238} O_{2}

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Solution

The correct option is A $H_{2}$ and $T_{2}$
According to graham's law of diffusion,
$R a t e o f e f f u s i o n \propto \frac{1}{\sqrt{m o l a r m a s s}}$
Molar mass of $C H_{4} = 12 + 4 = 16 g$
Molar mass of $N H_{3} = 14 + 3 = 17 g$
There are nearly equal $⟹$ separation becomes difficult.
$H_{2}$ and $T_{2}$ has large difference in molar masses.
$⟹$ Separation with rates of effusion is possible.

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