Under normal conditions- for the reaction SO3g-H2Ol- H2SO4aq the nature of -H is-

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Sulphur Trioxide

Under normal ...

Question

Under normal conditions, for the reaction $S O_{3} (g) + H_{2} O (l) \to H_{2} S O_{4} (a q)$ the nature of $Δ$ H is:

Negative

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Positive

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Zero

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Can’t be determined as data is insufficient

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Solution

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S_{(s)} + O_{2 (g)} \to S O_{2 (g)}; Δ H = - 298.2 k J

S O_{2 (g)} + \frac{1}{2} O_{2 (g)} \to S O_{3 (g)}; Δ H = - 98.7 k J

S O_{3 (g)} + H_{2} O_{(l)} \to H_{2} S O_{4 (l)}; Δ H = - 130.2 k J

H_{2 (g)} + \frac{1}{2} O_{2 (g)} \to H_{2} O_{(l)}; Δ H = - 287.3 k J

H_{2} S O_{4}

For the reaction $H_{2} O (s) ⇋ H_{2} O (l)$ at 0°C and normal pressure

H_{2} S O_{4 (a q)} + 2 K O H_{(a q)} \to K_{2} S O_{4 (a q)} + 2 H_{2} O_{(f)}; Δ H

S (s) + O_{2} (g) \to {S O}_{2} (g); Δ H^{\circ} = - 297 k J

2 {S O}_{2} (g) + O_{2} (g) \to 2 {S O}_{3} (g); Δ H^{\circ} = - 198 k J

S O_{3}

S (s) + \frac{3}{2} O_{2} (g) \to {S O}_{3} (g)

{Na}_{2} {CO}_{3} (aq) + H_{2} {SO}_{4} (aq) \to ?

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