Under similar conditions, how many times $H_{2}$ gas will diffuse as quickly as oxygen?

Two times

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Four times

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Three times

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Five times

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Solution

The correct option is B Four times
By Graham's Law we know that:
$\frac{r_{H_{2}}}{r_{O_{2}}} = \sqrt{\frac{M_{O_{2}}}{M_{H_{2}}}}$
where M = Molecular mass and r = rate of diffusion
$x = \sqrt{\frac{32}{2}} x = 4 t i m e s$

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Under similar conditions, how many times H2 gas will diffuse as quickly as oxygen?

The correct option is B Four times By Graham's Law we know that: rH2rO2=√MO2MH2 where M = Molecular mass and r = rate of diffusion x=√322x=4 times

Under similar conditions, how many times $H_{2}$ gas will diffuse as quickly as oxygen?

The correct option is B Four times
By Graham's Law we know that:
$\frac{r_{H_{2}}}{r_{O_{2}}} = \sqrt{\frac{M_{O_{2}}}{M_{H_{2}}}}$
where M = Molecular mass and r = rate of diffusion
$x = \sqrt{\frac{32}{2}} x = 4 t i m e s$