Under similar conditions of pressure and temperature, $40 m L$ of slightly moist $H C l$ gas is mixed with $20 m L$ of ammonia gas, the final volume of gas at the same temperature and pressure will be :

100 m L

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20 m L

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40 m L

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60 m L

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Solution

The correct option is B $20 m L$
NH3 + HCL --> NH4Cl
According to the given question, 1 ml NH3 reacts with 1 ml HCl to produce 1 ml of NH4Cl.
So, 20 ml of ammonia reacts with 20 ml of HCl to produce 20 ml of resultant NH4Cl. The rest of HCl will stay unreacted.
So, the correct option is '20ml'.

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Under similar conditions of pressure and temperature, 40 mL of slightly moist HCl gas is mixed with 20 mL of ammonia gas, the final volume of gas at the same temperature and pressure will be :

The correct option is B 20 mLNH3 + HCL --> NH4ClAccording to the given question, 1 ml NH3 reacts with 1 ml HCl to produce 1 ml of NH4Cl.So, 20 ml of ammonia reacts with 20 ml of HCl to produce 20 ml of resultant NH4Cl. The rest of HCl will stay unreacted.So, the correct option is '20ml'.

Under similar conditions of pressure and temperature, $40 m L$ of slightly moist $H C l$ gas is mixed with $20 m L$ of ammonia gas, the final volume of gas at the same temperature and pressure will be :

The correct option is B $20 m L$
NH3 + HCL --> NH4Cl
According to the given question, 1 ml NH3 reacts with 1 ml HCl to produce 1 ml of NH4Cl.
So, 20 ml of ammonia reacts with 20 ml of HCl to produce 20 ml of resultant NH4Cl. The rest of HCl will stay unreacted.
So, the correct option is '20ml'.