Under the action of a force, a 1kg body moves, such that its position x as a function of time t is given by x=t32 where x is in meter and t is in second. The work done by the force in first 3 second is
A
243J
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B
2430J
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C
7298
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D
24.3J
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Solution
The correct option is C7298
We can get acceleration by double differentiating x wrt t ,