You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Chemistry

Stoichiometric Calculations

Under the sam...

Question

Under the same conditions of temperature and pressure, 1 l of oxygen gas was mixed 1 l of carbon dioxide gas. The mass ration of the gases in the mixture will be:

1:1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

8:11

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

11:8

No worries! We‘ve got your back. Try BYJU‘S free classes today!

16:44

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is D 8:11
Molecular weight of $O_{2}$ = 32g
Molecular weight of $C O_{2}$ = 44g
Therefore the mass ratio of mixture of 1l of gases = $\frac{32}{44}$ = 8:11

Suggest Corrections

Similar questions

An enclosure of volume V contains a mixture of 8g of oxygen, 14g of nitrogen and 22g of carbon dioxide at absolute temperature T. The pressure of the mixture of gases is (R is universal gas constant)

Q. A mixture of gases in a cylinder at 760

m m

pressure contains 65% nitrogen, 15% oxygen, and 20% carbon dioxide by volume. What is the partial pressure of oxygen gas in

m m

40 m L

of slightly moist

H C l

gas is mixed with

20 m L

of ammonia gas, the final volume of gas at the same temperature and pressure will be :

Q. Hydrogen, oxygen and carbon dioxide are taken in containers of

2 l

volume each. Compare the number of molecules of the three gases under same conditions of temperature and pressure.

Q. A container holds

22.4

litre of a gas at

1

atmospheric pressure and at

0^{\circ} C

. The gas consists of a mixture of argon, oxygen and sulphur dioxide in which:
(a) Partial pressure of

S O_{2} =

(Partial pressure

O_{2}) +

(Partial pressure of

A r

).
(b) Partial pressure of

O_{2} = 2 \times

partial pressure of

A r

.
Calculate the density of the gas mixture under these conditions.

Join BYJU'S Learning Program

Under the same conditions of temperature and pressure, 1 l of oxygen gas was mixed 1 l of carbon dioxide gas. The mass ration of the gases in the mixture will be:

The correct option is D 8:11Molecular weight of O2 = 32gMolecular weight of CO2 = 44gTherefore the mass ratio of mixture of 1l of gases = 3244 = 8:11

The correct option is D 8:11
Molecular weight of $O_{2}$ = 32g
Molecular weight of $C O_{2}$ = 44g
Therefore the mass ratio of mixture of 1l of gases = $\frac{32}{44}$ = 8:11