Under the translation x-y-x-1-y-2the point -2-3 will become

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Standard XII

Physics

Unit Vectors

Under the tra...

Question

Under the translation $(x, y) \to (x - 1, y + 2)$ the point $(- 2, 3)$ will become

(- 3, 1)

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(- 1, 1)

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(- 3, 5)

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(- 1, 5)

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Solution

The correct option is D $(- 3, 5)$
Given the translation $(x, y) ⟶ (x - 1, y + 2)$
Substitute $(x, y) = (- 2, 3) ⟹ (- 2 - 1, 3 + 2) = (- 3, 5)$

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the point

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Q. Let X = {1, 2, 3, 4} and Y = {1, 5, 9, 11, 15, 16}
Determine which of the following sets are functions from X to Y.

(a) f₁ = {(1, 1), (2, 11), (3, 1), (4, 15)}
(b) f₂ = {(1, 1), (2, 7), (3, 5)}
(c) f₃ = {(1, 5), (2, 9), (3, 1), (4, 5), (2, 11)}

Let X = {1, 2, 3, 4} and Y = {1, 5, 9, 11, 15, 16}
Determine which of the following sets are functions from X to Y.
(i) $f_{1} = {(1, 1), (2, 11), (3, 1), (4, 15)}$
(ii) $f_{2} = {(1, 1), (2, 7), (3, 5)}$
(iii) $f_{3} = {(1, 5), (2, 9), (3, 1), (4, 5), (2, 11)}$

If the relation R:A $\to$ B where A={1,2,3,4} and B={1,3,5} is defined by R={(x,y):x<y,x $\in$ A,y $\in$ B}, then $R O R^{- 1}$ is

$Find what the following equations become when the origin is shifted to the point(1,1) ? (i) x^{2} + x y - 3 y^{2} - y + 2 = 0 (i i) x y - y^{2} - x + y = 0 (i i i) x y - x - y + 1 = 0 (i v) x^{2} - y^{2} - 2 x + 2 y = 0$

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Under the translation (x,y)→(x−1,y+2)the point (−2,3) will become

The correct option is D (−3,5)Given the translation (x,y)⟶(x−1,y+2)Substitute (x,y)=(−2,3)⟹(−2−1,3+2)=(−3,5)

Under the translation $(x, y) \to (x - 1, y + 2)$ the point $(- 2, 3)$ will become

The correct option is D $(- 3, 5)$
Given the translation $(x, y) ⟶ (x - 1, y + 2)$
Substitute $(x, y) = (- 2, 3) ⟹ (- 2 - 1, 3 + 2) = (- 3, 5)$