Under which condition stated below, the six-carbon glucose molecule is broken down into three-carbon molecules pyruvate and lactic acid?
A
Aerobic condition in muscle cells
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B
Anaerobic condition in yeast cells
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C
Aerobic condition in mitochondria
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D
Anaerobic condition in muscle cells
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Solution
The correct option is D Anaerobic condition in muscle cells When the muscles perform vigorous activity and there is less supply of oxygen, the cells perform anaerobic type of respiration. This respiration takes place in the absence of oxygen. Glucose is converted to 3 carbon compound pyruvate by glycolysis. In the absence of oxygen in muscles, pyruvate is converted to lactic acid.
Thus, the correct answer is 'Anaerobic condition in muscle cells'.