Question

$\underset{–}{{CH}_{3}CHO}+2{\left[Ag{\left({NH}_3\right)}_2\right]}^{+}+3{OH}^{-}⟶{CH}_{3}CO{O}^{-}+2Ag+4{NH}_3+2H_{2}O$

The equivalent weight of underlined compound when molecular weight is taken as $M$ is :

• A. $E=M$
• B. $E=\frac{M}{6}$
• C. $E=\frac{M}{4}$
• D. none of these

Answer 1

The correct option is A $E=M$

The average oxidation number of C in $C{H}_{3}CHO$ is $-1$.
The average oxidation number of C in $C{H}_{3}CO{O}^{-}$ is $0$.
Thus, the oxidation number of C changes by $1$.
$\text{Equivalent weight}=\frac{\text{Molecular weight}}{\text{Change in the oxidation number}}$
Hence, $E=\frac{M}{1}$