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Question

K2Cr2O7––––––––+7H2SO4+6FeSO4K2SO4+Cr2(SO4)3+3Fe2(SO4)3+7H2O
The equivalent weight of the underlined species (by taking its molecular weight as M) is :

A
E=M6
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B
E=M4
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C
E=M3
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D
none of these
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Solution

The correct option is A E=M6
The oxidation number of Cr in K2Cr2O7 is +6.
The oxidation number of Cr in Cr2(SO4)3 is +3.
Thus, the oxidation number of Cr changes by 3.
Total change in the oxidation number of two Cr atoms is 6.
Equivalent weight=Molecular weightChange in the oxidation number
Hence, E=M6

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