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Question

S2O23–––––+5H2O+4Cl22SO24+8Cl+10H+
The equivalent weight of the underlined compound by taking its molecular weight as M is :

A
E=M8
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B
E=M6
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C
E=M4
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D
none of these
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Solution

The correct option is A E=M8
The oxidation number of S in S2O23 is +2.
The oxidation number of in SO24 is +6.
The oxidation number of one S atom changes by 4.
Thus, the oxidation number of two S atom changes by 8.
Equivalent weight=Molecular weightChange in the oxidation number
Hence, E=M8

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