CH3a−CH2b−CH2c−CdH2−F Arrange the hydrogens a,b,c,d, in decreasing order of their reactivities towards chlorination:
A
a>b>c>d
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B
b>c>d>a
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C
b>c>a>d
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D
c>b>a>d
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Solution
The correct option is Cb>c>a>d Among all of them hydrogen 'b' will be most leachive towards chlorination as it is 2o hydrogen and it will get less electronegativity of fluorine atom and 'd' will be least stable as it is adjacent to the fluorine atom and does not have 3o−2o hydrogen.