Cyanic acidH-O-C-N- Isocyanic acidH - N - C - OLoss of proton from these two acids produces-

The correct option is A same anion (Cyanicacid) H O C=N → ^ O C=N ↔ O=C N^ (Isocyanicacid) H N=C=O → ^ N C=O ↔ N=C O^ Therefore they both ...

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Byju's Answer

Standard XII

Chemistry

Arrhenius Acid

Cyanic acidH-...

Question

$H - O - C = N (C y a n i c a c i d), H - N = C = O (I s o c y a n i c a c i d)$
Loss of proton from these two acids produces:

same anion

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different anions

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same cation

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different cations

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Solution

The correct option is A same anion
$H - O - C = N (C y a n i c a c i d) \to^{-} O - C = N \leftrightarrow O = C - N^{-} H - N = C = O (I s o c y a n i c a c i d) \to^{-} N - C = O \leftrightarrow N = C - O^{-}$
Therefore they both form same anion. Option A is correct.

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Similar questions

Q. HNCO (isocyanic acid) has following resonating structures:

H - N = C = O I \leftrightarrow H - ⊖ N - C \equiv \oplus O I I \leftrightarrow H - \oplus N \equiv C - ⊖ O I I I

The order of stability is:

Q. Find

A, B

and

C

in the following reactions:

$N H_{3} + A + C O_{2} \to {(N H_{4})}_{2} C O_{3}$

${(N H_{4})}_{2} C O_{3} + H_{2} O + B \to N H_{4} H C O_{3}$

$N H_{4} H C O_{3} + N a C l \to N H_{4} C l + C$

$S n C l_{2} .2 H_{2} O Δ \to ? - + H C l + H_{2} O$

Q. HNCO (isocyanic acid) has following resonating structures:

H - N = C = O I \leftrightarrow H - ⊖ N - C \equiv \oplus O I I \leftrightarrow H - \oplus N \equiv C - ⊖ O I I I

The order of stability is:

Q. Find A, B and C in the following reactions

N H_{3} + A + C O_{2} \to (N H_{4}) C O_{3}

(N H_{4})_{2} C O_{3} + B \to C a C O_{3} ↓ + 2 N H_{4} C l

N H_{4} H C O_{3} + N a C l \to N H_{4} C l + C

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H−O−C=N(Cyanic acid), H−N=C=O(Isocyanic acid)Loss of proton from these two acids produces:

The correct option is A same anionH−O−C=N(Cyanicacid)→−O−C=N↔O=C−N−H−N=C=O(Isocyanicacid)→−N−C=O↔N=C−O−Therefore they both form same anion. Option A is correct.

$H - O - C = N (C y a n i c a c i d), H - N = C = O (I s o c y a n i c a c i d)$
Loss of proton from these two acids produces:

The correct option is A same anion
$H - O - C = N (C y a n i c a c i d) \to^{-} O - C = N \leftrightarrow O = C - N^{-} H - N = C = O (I s o c y a n i c a c i d) \to^{-} N - C = O \leftrightarrow N = C - O^{-}$
Therefore they both form same anion. Option A is correct.