Question

$\underset{\text{Specific Rotaion}=+{50}^o}{Ph-CH\left(OH\right){CH}_3}\underset{}{\overset{SO{Cl}_2}{\to }}\underset{|Cl}{PhCl}-{CH}_3$
What is the specific rotation of the product?

• A. $+{50}^o$
• B. $+{60}^o$
• C. $-{60}^o$
• D. Zero

Answer 1

Answer: (B)

$+{60}^o$

It is an example of $S{N}^1$ reaction, in which retention takes place. So, if reactant-specific rotation is positive, it should be positive for the product also, but of different value since, the reactant and product are different. Thus, the specific rotation of the product is $+{60}^0$.