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Question

limx0(1+2x1+3x)1x2.e1x=

A
e52
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B
e2
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C
2
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D
1
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Solution

The correct option is A e52
limx0e1x2(log(1+2x)log(1+3x))+1xelimx0(log(1+2x)log(1+3x))+xx2
Using the expansion we get -
=e52

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