Ltx - 0-sin-3-x-sin-3-x-x is equal to

The correct option is C x→ 0Lt2cos π/5sin(x)/x=2cos π/5 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Expansions to Remove Indeterminate Form

Ltx → 0=sinπ/...

Question

$L t x \to 0 = \frac{s i n (\frac{π}{5} + x) - s i n (\frac{π}{5} - x)}{x}$ is equal to

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

Suggest Corrections

Similar questions

lim x \to 0 \frac{sin x \times sin (\frac{π}{3} + x) sin (\frac{π}{3} - x)}{x}

sin \frac{π [x]}{12} + cos \frac{π [x]}{4} + tan \frac{π [x]}{3}

[x]

x

Q = ⎡ ⎢ ⎢ ⎣ \begin{matrix} cos \frac{π}{4} & - sin \frac{π}{4} sin \frac{π}{4} & cos \frac{π}{4} \end{matrix} ⎤ ⎥ ⎥ ⎦

x = ⎡ ⎢ ⎢ ⎢ ⎢ ⎣ \begin{matrix} \frac{1}{\sqrt{2}} \frac{1}{\sqrt{2}} \end{matrix} ⎤ ⎥ ⎥ ⎥ ⎥ ⎦

Q^{3} x

{⎛ ⎜ ⎜ ⎜ ⎝ \frac{cos (\frac{π}{2} + x) + sin (\frac{π}{2} + x)}{cos (\frac{π}{2} - x) - sin (\frac{π}{2} - x)} ⎞ ⎟ ⎟ ⎟ ⎠}^{2}

{⎡ ⎢ ⎢ ⎢ ⎢ ⎣ \frac{sin \frac{π}{6} + i (1 - cos \frac{π}{6})}{sin \frac{π}{6} - i (1 - cos \frac{π}{6})} ⎤ ⎥ ⎥ ⎥ ⎥ ⎦}^{3}

i = \sqrt{- 1}

Join BYJU'S Learning Program