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Byju's Answer
Standard XII
Mathematics
Differentiation under Integral Sign
lim x →π/4∫2∫...
Question
l
i
m
x
→
π
4
∫
s
e
c
2
x
2
f
(
t
)
d
t
x
2
−
π
2
16
equals
A
8
π
f
(
2
)
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B
2
π
f
(
2
)
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C
2
π
f
(
1
2
)
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D
4
f
(
2
)
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Solution
The correct option is
A
8
π
f
(
2
)
Required limits is of the form
0
0
, so it is equal to
l
i
m
x
→
π
4
2
s
e
c
x
s
e
c
x
t
a
n
x
f
(
s
e
c
2
x
)
2
x
=
l
i
m
x
→
π
4
s
e
c
2
x
t
a
n
x
f
(
s
e
c
2
x
)
x
=
8
π
f
(
2
)
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1
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