limx→−∞[x4sin(1x)+x21+|x|3] limx→−∞x31+|x|3[xsin(1x)+1x] As x→−∞ x31+|x|3=−1 x sin(1x)+1x=1 ⇒limx→−∞x31+|x|3(x sin1x+1x)=−1