Uniform electric field of 10NC^-1 exist in the vertically downward direction find the increase is electric potential as one goes up through a height of 50 cm

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Solution

We know,

V = -E.d [bold letters represent vector quantities]

=> V = -Ed cosθ [θ is the angle between E and d, here it is 1800]

=> V = -(10)(0.5)(-1) [50 cm = 0.5 m]

=> V = 5 V

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Uniform electric field of 10NC-1 exist in the vertically downward direction find the increase is electric potential as one goes up through a height of 50 cm

We know, V = -E.d [bold letters represent vector quantities] => V = -Ed cosθ [θ is the angle between E and d, here it is 1800] => V = -(10)(0.5)(-1) [50 cm = 0.5 m] => V = 5 V

Uniform electric field of 10NC^-1 exist in the vertically downward direction find the increase is electric potential as one goes up through a height of 50 cm

We know,

V = -E.d [bold letters represent vector quantities]

=> V = -Ed cosθ [θ is the angle between E and d, here it is 1800]

=> V = -(10)(0.5)(-1) [50 cm = 0.5 m]

=> V = 5 V