Uniform electric field of magnitude 100V/m in space is directed along the line $y = 3 + x$ . Find the potential difference between point $A (3, 1)$ and $B (1, 3)$ :

100 V

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200 \sqrt{2}

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200 V

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0

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Solution

The correct option is C $0$
Potential difference between A and B is
$V_{B A} = - E d x - E d y = - 100 (1 - 3) - 100 (3 - 1) = 200 - 200 = 0 V$

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Uniform electric field of magnitude 100V/m in space is directed along the line y=3+x. Find the potential difference between point A(3,1) and B(1,3):

The correct option is C 0Potential difference between A and B is VBA=−Edx−Edy=−100(1−3)−100(3−1)=200−200=0V

Uniform electric field of magnitude 100V/m in space is directed along the line $y = 3 + x$ . Find the potential difference between point $A (3, 1)$ and $B (1, 3)$ :

The correct option is C $0$
Potential difference between A and B is
$V_{B A} = - E d x - E d y = - 100 (1 - 3) - 100 (3 - 1) = 200 - 200 = 0 V$