Unit cell edge length of $C s C l$ arrangement is $400$ pm. Calculate the interionic distance in $C s C l$ .

346.4

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150.2

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112.4

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None of the above

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Solution

The correct option is A $346.4$ pm
$C s C l$ arranges in body centred type structure
For body centred structures $\sqrt{3} a = 4 r$
$⟹ \sqrt{3} \times 400 = 4 r$
$⟹ r = 173.2$ pm
The interionic distance $= 2 r = 346.4$ pm

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