Question

Unit digit of a number is 3 more than the tens digit. If the number obtained by interchanging the digits 27 more than the original number. Go d the sum of the digits of the smaller number

Answer 1

Given units digit is x+3
and tens digit is x
Hence the two digit number = 10x+x+3 =11x+3
Number obtained by reversing the digits = 10(x+3)+x=11x+30
Given the original is 27 more than the number obtained by reversing the digits.
Hence 11x+3= 11x+30 + 27
⇒54=0


this is a wrong statement
i.e there are many solution for this statement
the solutions are 14,25,36,47,58,69

these numbers all satisfy the given condition