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Standard XII

Chemistry

Characteristics of Chemical Equilibrium

Unit of equil...

Question

Unit of equilibrium constant for the following reaction is :
$P {C l}_{5} ⇌ P {C l}_{3} + {C l}_{2}$

{d m}^{3} / m o l e

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m o l e / {d m}^{3}

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{(m o l e / {d m}^{3})}^{2}

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{({d m}^{3} / m o l e)}^{2}

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Solution

The correct option is B $m o l e / {d m}^{3}$
Unit of equilibrium constant for the following reaction is $m o l e / {d m}^{3}$ .
$P {C l}_{5} ⇌ P {C l}_{3} + {C l}_{2}$
The equilibrium constant
$K_{c} = \frac{[P C l_{3}] \times [C l_{2}]}{[P C l_{5}]}$
$K_{c} = \frac{m o l e / {d m}^{3} \times m o l e / {d m}^{3}}{m o l e / {d m}^{3}}$
$K_{c} = m o l e / {d m}^{3}$

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Similar questions

Q. A quantity of

P C l_{5}

was heated in 10

d m^{3}

vessel

250^{o}

P C l_{5}

(g) ⇌

P C l_{3}

(g) +

C l_{2}

(g)

At equilibrium the vessel contains 0.1 mole of

P C l_{5}

and 0.2 mole of

C l_{2}

The equilibrium constant of the reaction is:

Q. A quantity of

P C l_{5}

was heated in

10 d m^{3}

vessel

250^{0} C

P C l_{5}

g) ⇌

P C l_{3}

(g) +

C l_{2}

(g)
At equilibrium the vessel contains 0.1 mole of

P C l_{5}

and 0.2 mole of

C l_{2}

. The equilibrium constant of the reaction is ?

Q. 2 mole each of

P C l_{5}

and

C l_{2}

and 1 mole of

P C l_{3}

are taken in 5lt. flask at

27^{o} C

. After following equilibrium is attained in gaseous phase,

P C l_{5} ⇌ P C l_{3} + C l_{2}, P C l_{5}

is found to be 40% dissociated. Calculate equilibrium constant

K_{c}

0.6

mole of

P C l_{5}

0.3

mole of

P C l_{3}

and

0.5

mole of

C l_{2}

are taken in a

1

L flask to obtain the following equilibrium:

P C l_{5 (g)} ⇌ P C l_{3 (g)} + C l_{(} 2 g)

If the equilibrium constant

K_{c}

for the reaction is

0.2

. Predict the direction of the reaction.

Q. In the reaction,

P C l_{5} ⇌ P C l_{3} + C l_{2}

, the amount of

P C l_{5}, P C l_{3}

and

P C l_{2}

at equilibrium are

2

moles each and the total pressure is

3

atm. The equilibrium constant

K_{p}

is:

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Unit of equilibrium constant for the following reaction is : PCl5⇌PCl3+Cl2

The correct option is B mole/dm3Unit of equilibrium constant for the following reaction is mole/dm3. PCl5⇌PCl3+Cl2The equilibrium constant Kc=[PCl3]×[Cl2][PCl5]Kc=mole/dm3×mole/dm3mole/dm3Kc=mole/dm3

Unit of equilibrium constant for the following reaction is :
$P {C l}_{5} ⇌ P {C l}_{3} + {C l}_{2}$