Unit of equilibrium constant $K_{c}$ for following homogenous reaction :-
$4 N H_{3} + 5 O_{2} ⇌ 4 N O + 6 H_{2} O$ is

(C o n c e n t r a t i o n)^{- 1}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(C o n c e n t r a t i o n)^{+ 1}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

(C o n c e n t r a t i o n)^{+ 2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Have no unit

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $(C o n c e n t r a t i o n)^{+ 1}$
$4 N H_{3} + 5 O_{2} ⇌ 4 N O + 6 H_{2} O$
$K_{c} = [H_{2} O]^{6} [N O]^{4} / [O_{2}]^{5} [N H_{3}]^{4}$
so unit of $K_{c}$ is $(C o n c e n t r a t i o n)^{+ 1}$ .

Suggest Corrections

Similar questions

4 N H_{3} + 5 O_{2} ⇌ 4 N O + 6 H_{2} O

K_{c}

{4 N H}_{3} + {5 O}_{2} ⇌ 4 N O + {6 H}_{2} O

4 N H_{3} + 5 O_{2} \to 4 N O + 6 H_{2} O

The catalyst used in $4 N H_{3} + 5 O_{2} ⟶ 4 N O + 6 H_{2} O$ is___________.

For which of the following reactions does the equilibrium constant

depend on the units of concentration

Join BYJU'S Learning Program