Unit of magnetic induction $B$ is :

\frac{N}{A m}

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\frac{N A}{m}

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\frac{N m}{A}

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\frac{N}{A}

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Solution

The correct option is A $\frac{N}{A m}$
$F = \int i (\to d l \times \to B)$

Hence unit of $B :$ unit of $\frac{F}{i \times d l}$

Since unit of $F$ is Newton, unit of $i$ is Amp and unit of $d l$ is $m$ unit of $B$ is $\frac{N}{A m}$

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Similar questions

The force acting on a pole of strength of 20 Am is 8x10 $^{- 4}$ N, when placed in a magnetic field. The magnetic induction field strength is :

(\frac{a^{m}}{a^{- n}})^{m - n} \times (\frac{a^{n}}{a^{- 1}})^{n - 1} \times (\frac{a^{1}}{a^{- m}})^{1 - m} =

B

B^{2} / N μ_{0}

N

M = a (m + n)

N = b (m - n)

(\frac{M}{a} + \frac{N}{b}) \div (\frac{M}{a} - \frac{N}{b})

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