Question

Unless stated otherwise use $\pi =\frac{22}{7}$.

The radii of two circles are $8cm$ and $6cm$ respectively. Find the radius of the circle having an area equal to the sum of the areas of the two circles.

Answer 1

$r_1=8cm,r_2=6cm$

$Let{}^{\prime }{r}^{\prime }betherequiredradiusofthecircle$

$then,$

$\pi r^2=\pi {r_1}^2+\pi {r_2}^2$

$r^2=8^2+6^2$

$r^2=64+36$

$r^2=100$

$r=10$