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Question

# Unpolarized light of intensity I passes through an ideal Polarizer A. Another identical polarizer B is placed behind A. The intensity of light beyond B is found to be I2. Now another identical polarizer C is placed between A and B. The intensity beyond B is now found to be I8. The angle between polarizer A and C is

A
60
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B
0
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C
30
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D
45
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Solution

## The correct option is D 45∘ From figure, it can be seen that the pass axis of A and B are parallel. When polarizer C is introduced between A and B: Intensity of plane polarized light when passed through C I′=I2cos2θ ....(1) Intensity of light when passed through B I′′=I′cos2θ but I′′=I8 ∴I8=I2cos2θ×cos2θ [from eqn (1)] ⇒cos4θ=14 ⇒cosθ=±1√2 ∴θ=45∘or θ=135∘ Hence, option (D) is correct.

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