Question

Upon fully dissolving 2.0 g of a metal in sulfuric acid, 6.8 g of the metal sulfate is formed. The equivalent weight of the metal is:

• A. 13.6 g
• B. 20.0 g
• C. 4.0 g
• D. 10.0 g

Answer 1

Answer: (B)

20.0 g

$\text{Equivalents of metal}=\text{Equivalents of metal sulphate}$

$\frac{\text{Wt.of metal}}{\text{Eq. wt. of metal}}=\frac{\text{Wt. of metal sulphate}}{\text{Eq. wt. metal sulphate}}$

$\frac{2}{x}=\frac{6.8}{x+48}$

$6.8x=2x+96$

$4.8x=96$

$x=\frac{96}{4.8}=20$

Hence, the equivalent mass of the metal is $20.0$ g.