Upon heating with $C u_{2} S$ , the reagents that give copper metal is/are

C u F e S_{2}

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C u O

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C u_{2} O

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C u S O_{4}

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Solution

The correct option is D $C u S O_{4}$
The trick is to get to Copper (I) oxide, which undergoes self-reduction:
During self reduction,
$2 C u_{2} O + C u_{2} S Δ - \to 6 C u + S O_{2}$

For this to happen, look for compounds that eventually lead to $C u_{2} O$ :

This reaction is characteristic of Copper (II) Oxide:
$4 C u O 1373 K - --- \to 2 C u_{2} O + O_{2}$

Also, Copper (II) Sulphate on heating gives Copper (II) oxide:
$2 C u S O_{4} 1093 K - --- \to 2 C u O + 2 S O_{2} + O_{2}$

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