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Question

Upon inserting a parallel-sided slab of glass between the lens and the screen, it was found necessary to move the screen a distance d away from the lens in order for the image to be again sharply focussed. If the refractive index of glass relative to air is μ then the thickness of the slab is:

A
dμ
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B
μd
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C
μd(μ1)
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D
(μ1)dμ
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Solution

The correct option is C μd(μ1)
Let the thickness of the screen is t
shift after entering the glass slab =d

According to formula,

Shift =(11μ)t

t=d(11μ)=μd(μ1)

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