Question

Upon treatment with ammoniacal $H_{2}S$, the metal ion solutions that precipitates as sulphide is ________.

1. Fe(III)

2. Zn(II)

Answer 1

${Zn}^{2+}$ will give zinc sulphide, upon treating with ammonical $H_{2}S$. i.e.

${Zn}^{2+}+H_{2}S\to ZnS+2H^{+}$

where as ${Al}^{3+}$ and ${Fe}^{3+}$ from respective hydroxide and ${Mg}^{2+}$ from respective bicarbonate upon treating with ammonical $H_{2}S$.