Question

Upon treatment with $I_2$ and aqueous $NaOH$, which of the following compounds will form iodoform?

• A. $C{H}_{3}C{H}_{2}C{H}_{2}C{H}_{2}CHO$
• B. $C{H}_{3}C{H}_{2}COC{H}_{2}C{H}_3$
• C. $C{H}_{3}C{H}_{2}C{H}_{2}C{H}_{2}C{H}_{2}OH$
• D. $C{H}_{3}C{H}_{2}C{H}_{2}CH\left(OH\right)C{H}_3$

Answer 1

The correct option is D $C{H}_{3}C{H}_{2}C{H}_{2}CH\left(OH\right)C{H}_3$

All alcohols undergo iodoform reaction containing $C{H}_{3}CH\left(OH\right)$ groups.

In the give options, only 4th option has $C{H}_{3}CH\left(OH\right)$ group. it will undergo iodoform reaction.

Option D is correct.