Upper part of a vertical tree which is broken over by the winds just touches the ground and makes an angle of $30^{o}$ with the ground. If the length of the broken part is $20$ metres, then the remaining part of the tree is of length.

20

metres

No worries! We‘ve got your back. Try BYJU‘S free classes today!

10 \sqrt{3}

metres

No worries! We‘ve got your back. Try BYJU‘S free classes today!

10

metres

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

10 \sqrt{2}

metres

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $10$ metres
$\frac{A B}{20 m} = sin 30^{o}$
$A B = 10 m$

Suggest Corrections

Similar questions

Q. Upper part of a vertical tree which is broken over by the winds just touches the ground and makes as angle of

30^{\circ}

with the ground if the length of the broken part is 20 metres then remaining part of the tree is of length

A tree is broken by wind and its upper part touches the ground at a point $10$ metres from the foot of the tree and makes an angle of $45^{\circ}$ with the ground. The entire length of the tree is

Q. Upper part of a vertical tree which is broken over by the winds just touches the ground and makes an angle of

30^{0}

with the ground. If the length of the broken part is 20 metros, then the remaining part of the tree is of length

A tree 10(2+ $\sqrt{3}$ ) metres high is broken by the wind at a height 10 $\sqrt{3}$ metres from its root in such a way that top struck the ground at certain angle and horizontal distance from the root of the tree to the point where the top meets the ground is 10 m. Find the angle of elevation made by the top of the tree with the ground.

Join BYJU'S Learning Program

Upper part of a vertical tree which is broken over by the winds just touches the ground and makes an angle of 30o with the ground. If the length of the broken part is 20 metres, then the remaining part of the tree is of length.

The correct option is C 10 metresAB20m=sin30oAB=10m

Upper part of a vertical tree which is broken over by the winds just touches the ground and makes an angle of $30^{o}$ with the ground. If the length of the broken part is $20$ metres, then the remaining part of the tree is of length.

The correct option is C $10$ metres
$\frac{A B}{20 m} = sin 30^{o}$
$A B = 10 m$