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Question

Uranium has two isotopes of masses 235 and 238 units . If both are present in uranium hexafluoride gas which would have the larger average speed ? If atomic mass of fluorine is 19 units , estimate the percentage difference in speeds at any temperature

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Solution

At a fixed temperature, kinetic energy of gas molecules is constant. Kinetic energy is given by
K. E equals 1 half m v squared

Rearranging, we get
K E equals 1 half m v squared rightwards double arrow v squared equals fraction numerator 2 cross times K E over denominator m end fraction rightwards double arrow v equals square root of fraction numerator 2 cross times K E over denominator m end fraction end root rightwards double arrow v space alpha space fraction numerator 1 over denominator square root of m end fraction

Therefore, smaller the mass of molecule, higher will be its speed.

The masses of the 2 types of uranium hexafluorides are
U to the power of 235 F subscript 6 equals 235 plus 6 cross times 19 equals 349 U to the power of 238 F subscript 6 equals 238 plus 6 cross times 19 equals 352

Therefore, the U-235 hexafluoride is faster.


Taking the ratios of their velocity
v subscript 235 over v subscript 238 equals fraction numerator begin display style fraction numerator 1 over denominator square root of 349 end fraction end style over denominator begin display style fraction numerator 1 over denominator square root of 352 end fraction end style end fraction space space space space space space space space space space equals fraction numerator square root of 352 over denominator square root of 349 end fraction space space space space space space space space space space space equals 1.0043

Therefore, the percentage difference is 0.43%.





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