Uranium react with $c o n c . H N O_{3}$ ;

to give

U (N O_{3})_{4}

and

H_{2}

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to give

U (N O_{3})_{2}

and

N O_{2}

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U O_{2} (N O_{3})_{2}

and

H_{2}

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to make metal passive

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Solution

The correct option is C to make metal passive
Uranium is soluble in nitric acid. It reacts with nitric acid slowly. The reaction of uranium with conc. nitric acid makes metal passive. The reaction of finely divided or powdered uranium metal with nitric acid is violent.

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