urea is a very important nitrogenous fertilizer.Its formlais CON2H4.Calculate the percentage of nitrogen in urea.(C=12,O=1,N=14 and H=1)

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Solution

urea=> NH₂-CO-NH₂

total mass=60

mass of nitrogen = 14, 2 molecules hence m=28

N%= mass of nitrogen X 100

mass of urea

= 28 X 100

N%= 46.6%

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urea is a very important nitrogenous fertilizer.Its formlais CON2H4.Calculate the percentage of nitrogen in urea.(C=12,O=1,N=14 and H=1)

urea=> NH2-CO-NH2 total mass=60 mass of nitrogen = 14, 2 molecules hence m=28 N%= mass of nitrogen X 100 mass of urea = 28 X 100 60 N%= 46.6%

urea=> NH₂-CO-NH₂

total mass=60

mass of nitrogen = 14, 2 molecules hence m=28

N%= mass of nitrogen X 100

mass of urea

= 28 X 100

60

N%= 46.6%