wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Urea solution has a molarity of 4.0 mol L1 and molality 4.0 mol kg1 H2O. Thus, the density (g mL1) of the solution is (Report the answer upto two decimals)

Open in App
Solution

1000 mL solution = 4.0 moles urea = 240 g urea
Since, mV= density (d)
Mass =V×d
1000×d g solution =240 g urea
Solvent (H2O)=(1000 d240)g=(1000 d2401000) kg
Molality =4 mol×1000(1000 d240) mol kg1
Given, molality =4 mol kg1
4000(1000 d240)=4
=40004=(1000 d240)
1000=1000 d240
1000 d=1240
d=1.24 g mL1
Note: We can calculate density by the following relation,
Molality =1000×molarity(M)[1000 dMm1(molar mass)]

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Reactions in Solutions
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon